Speakychat.org API Cheat Sheet
Speakychat.org API Cheat Sheet
I Want to know how can I unban my from World chat room by using this command now it shows You can use Text
Either it is Free(Anonymous) version or Paid(Premium) version. 64Bit
However, You cannot upload image directly.
In this, I want to show You how you can download this version with some features of this.
1. 64 bit
2. 16 Bit
You can use this command to download this software in Linux Ubuntu.
Download Software from Internet You can use Synaptic.
How you want to download software through Synaptic, enter:
Enter name: Speakychat
Enter: Released: 2019-02-05
Enter: For All
Enter: Local / Community
Enter: All Available Depedencies
Enter: Name: pangi-py-voice-profile-ui.
Enter: URL: DownloadOnline.
Enter: Option: Download
Enter: Packages to download:
Enter: Search All
Enter: Download All
3. What’s New in version. 2019-02-05
4. What’s New in version. 2017-02-05
5. What’s New in version. 2018-02-12
It is Free Software.
However, You can use this software to chat or make voice calls with friends. You can keep one voice call active at a time.
It is not an offline app, it keeps in online.
(While calling, if you are offline, they will call you or your friend, according to your online status.)
With this software, You can chat with both worldwide people at one time and also you can use our ‘Call’ feature and you can use your microphone for every conversation.
You have to create an account to chat on the website and then sign into chat with your username and email address.
While chatting on the website, You can use more features like sending files, images and voice and using of different groups to communicate or make groups.
While chatting on the website, You can choose to have a voice call with your friends, your family and your friends you want to make voice call.
You can make voice call from free calls or paid calls.
While chatting on the website, You can use this
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Mysql and php 5 syntax problem
I am trying to learn php 5’s mysql syntax and i’m having trouble with some basic stuff.
here is my php code:
prepare(“SELECT * FROM stories
$fav = $rs->fetchAll();
this code is pretty basic. It just outputs the database row from the stories table. ( the bl_author column is the author of the story)
Here is the error I am getting:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ‘WHERE bl_author=?’ at line 1
As far as i know, the bl_author field should be the WHERE clause of the query (see the manual). I am confused about where and why i am getting this error.
Thanks for any help.
Here is the error log in phpmyadmin:
The database server is complaining about a SQL injection vulnerability, because the prepared statement doesn’t have the quoted value of the WHERE clause. By using the correct escaping rules for field names, such as “, you can make sure that the query is safe. I would also recommend that you use the parametrized version of execute() (which is what that error implies) if possible, although the manual page makes it sound like it’s not mandatory in this case.
$rs = $dbc->prepare(‘SELECT * FROM stories WHERE bl_author=